Let the number be x and so if x+13 = 75 then the value of x must be 62
4
4
If the number (count) of odd values to sum is odd, then the answer is odd.If the number (count) of odd values to sum is even, then the answer is even.
[(x+3)^2] - [(x+2)^2] = 13 ==> 2x = 8 ==> x = 4. the number is 4!
If you mean: (x+3)^2 = (x+2)^2 +13 Then the value of the number x works out as 4
If I read this correctly, you're asking to solve the equation (x + 3)2 = (x + 2)2 + 13. That becomes x2 + 6x + 9 = x2 + 4x + 4 + 13 6x + 9 = 4x + 17 2x = 8 x = 4 Check it. 49 = 36 + 13 It checks.
3 + 23 7 + 19 13 + 13
31 Because, twice 31 is 62. And, 62 plus 13 is 75.
The number is 4 (4+3) * (4+3) = 49 (4+2) * (4+2) = 36 49 - 36 = 13
Count how many of the numbers are odd. If an odd number of them are odd, then their sum is odd. If an even number of them are odd, then their sum is even.
the sum of 67 + 13 = 80
26