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What is two-fifths of 4?


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Answered 2011-01-31 00:43:06

two-fifths of 4 = 1.6

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Is fourfifteenths greater than twofifths?

no


What is twofifths of 52?

It is: 2/5 of 52 = 20.8


How do you get 1-50 with only the numbers 1 2 3 and 4?

1 2 3 4 4+1 4+2 4+3 4+4 4+4+1 4+4+2 4+4+3 4+4+4 4+4+4+1 4+4+4+2 4+4+4+3 4+4+4+4 4+4+4+4+1 4+4+4+4+2 4+4+4+4+3 4+4+4+4+4 4+4+4+4+4+1 4+4+4+4+4+2 4+4+4+4+4+3 4+4+4+4+4+4 4+4+4+4+4+4+1 4+4+4+4+4+4+2 4+4+4+4+4+4+3 4+4+4+4+4+4+4 4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+4+4+2 4+4+4+4+4+4+4+4+4+4+4+3 4+4+4+4+4+4+4+4+4+4+4+4 4+4+4+4+4+4+4+4+4+4+4+4+1 4+4+4+4+4+4+4+4+4+4+4+4+2 I hope this is the answer you search for! (because it took some time!)


How can you make numbers 1-25 out of fours?

26


what is 4+4+4+4+4+4+4+4+4+4=what?

4 +4+4+4+4+4+4+4+4=40


Using the number 4 four times can you make 1-100?

1 = 4*4/(4*4) 2 = 4/4+4/4 3 = (4+4+4)/4 4 = (4-4)/4+4 5 = 4^(4-4)+4 6 = (4+4)/4+4 7 = 4+4-4/4 8 = 4+4+4-4 9 = 4/4+4+4 10 = (4*4+4!)/4 11 = (4+4!)/4+4 12 = (4-4/4)*4 13 = (4+4!+4!)/4 14 = 4!/4+4+4 15 = 4*4-4/4 16 = 4*4+4-4 17 = 4*4+4/4 18 = (4*4!-4!)/4 19 = 4!-(4+4/4) 20 = (4/4+4)*4 21 = 4!+4/4-4 22 = 4!-(4+4)/4 23 = 4!-4^(4-4) 24 = 4*4+4+4 25 = 4!+(4/4)^4 26 = 4!+4!/4-4 27 = 4!+4-4/4 28 = (4+4)*4-4 29 = 4/4+4!+4 30 = (4*4!+4!)/4 31 = (4+4!)/4+4! 32 = 4^4/(4+4) 33 = (4-.4)/.4+4! 34 = 4!/4+4+4! 35 = (4.4/.4)+4! 36 = (4+4)*4+4 37 = 4/.4+4+4! 38 = 44-4!/4 39 = (4*4-.4)/.4 40 = (4^4/4)-4! 41 = (4*4+.4)/.4 42 = 4!+4!-4!/4 43 = 44-4/4 44 = 4*4+4+4! 45 = (4!/4)!/(4*4) 46 = (4!-4)/.4 - 4 47 = 4!+4!-4/4 48 = (4*4-4)*4 49 = 4!+4!+4/4 50 = (4*4+4)/.4 51 = 4!/.4-4/.4 52 = 44+4+4 53 = 44+4/.4 54 = (4!/4)^4/4! 55 = (4!-.4)/.4-4 56 = 4!+4!+4+4 57 = 4/.4+4!+4! 58 = (4^4-4!)/4 59 = 4!/.4-4/4 60 = 4*4*4-4 61 = 4!/.4+4/4 62 = (4!+.4+.4)/.4 63 = (4^4-4)/4 64 = 4^(4-4/4) 65 = 4^4+4/4 66 = (4+4!)/.4-4 67 = (4+4!)/.4+4 68 = 4*4*4+4 69 = (4+4!-.4)/.4 70 = (4^4+4!)/4 71 = (4!+4.4)/.4 72 = (4-4/4)*4! 73 = (.4√4+.4)/.4 74 = (4+4!)/.4+4 75 = (4!/4+4!)/.4 76 = (4!-4)*4-4 77 = (4!-.4)/.4+4! 78 = (4!*.4+4!)/.4 79 = (.4√4-.4)/.4 80 = (4*4+4)*4 81 = (4/4-4)^4 82 = 4!/.4+4!+4 83 = (4!-.4)/.4+4! 84 = (4!-4)*4+4 85 = (4/.4+4!)/.4 86 = (4-.4)*4!-.4 87 = 4!*4-4/.4 88 = 4^4/4+4! 89 90 = (4!/4)!/(4+4) 91 92 = (4!-4/4)*4 93 94 = (4+4!)/.4 + 4! 95 = 4!*4-4/4 96 = 4!*4+4-4 97 = 4!*4+4/4 98 = (4!+.4)*4+.4 99 = (4!+4!-4)/.4 100 = 4*4/(.4*.4)


How do you get 27 only using 4 fours?

(4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4) ÷ 4 = 27


How do you get 13 using 4 fours?

1 = 44 / 44 2 = 4 * 4 / (4 + 4) 3 = (4 + 4 + 4) / 4 4 = 4 + (4 * (4 - 4)) 5 = (4 + (4 * 4)) / 4 6 = 4 + ((4 + 4) / 4) 7 = (44 / 4) - 4 8 = 4 + 4 + 4 - 4 9 = 4 + 4 + (4 / 4) 10 = (44 - 4) / 4 11 = (4 / 4) + (4 / .4) 12 = (4 + 44) / 4 13 = 4 + ((4 - .4) / .4) 14 = (4 * (4 - .4)) - .4 15 = 4 + (44 / 4) 16 = (44 - 4) * .4 17 = (4 * 4) + (4 / 4) 18 = (44 * .4) + .4 19 = (4 + 4 - .4) / .4 20 = 4 * (4 + (4 / 4))


What are the answers for the four fours problem?

Ericrain-0 = 4+4-4-41= 44/442= 4/4 + 4/43= (√4x4) - 4/44= 4! - 4x4 - 45= √4x4 +4/46= (4+4)/4 + 47=(4!/4+4) + 48=(4+4) x 4/49= 4+4+4/410= (44-4)/411=4/.4+4/412=4!-(4+4) -413=(4!√4+4)/414=4/.4+√4√415=4x4 - 4/416=4+4+4+417=(4x4) + 4/418= (44x.4)+.419=4!-4-4/420=4/.4 + 4/.421=4!-4+4/422=4!-4+ 4/√423=4!-√4+4/424=4! √4x4/425=4!+√4 - 4/426=(4x4) + 4/.427= √√√(4!/4√4)^4!28=4(4+4)-429=4!+4+4/430=4!-√4 +4+431=4!-√4 =√4/432=4^4 /4+433=4!+4+√4/434=4!+4+4+√435= 4!+4+4+√436=4!+4+4+437=4! + 4!+√4 /√438=4!-√4 +(4x4)39=44- √4/440=4! + (√4x√4x4)41=4! + √4/.4 -4!42=44- 4/√443= 44-4/444=44 x 4/445=44+4/446=4!+4! -4 + √447=4! x √4-4/448=4/4 (4!+4!)49=4/4 + (4!+4!)50= (4+4)/(.4x.4)51=4!-√4 /4 -452= 44+4+453=4! +4! = √4/.454=4!+4! + √4/.455=4!/.4 - √4/.456=4!+4! +4 +457=4! - √4/.4 +√458=√4!x4!/4 - √459=4!/.4 -4/460=4x4 + 4461=4!/.4 +4/462=4!/.4+√√4x463=4!+√4/4 - √464=4^4-4/465=4!/.4 + √4/.466=4!/.4 + 4!/467=4! + √4/.4 + √468=4^4 /4 +469=4!+√4 /.4 +470=(4x4!)-4! - √471=4!+4.4 /.472=4!+4!/4√473=√√√4^4! +4/.474=(4x4!)-4! + √475=4+4+√4/.476=4!/.4 +(4x4)77=4!/.4 √.4 -478= 4/.04 -4! + √479=4!/.4 √.4 -√480=4/.4 x (4+4)81=9d-4/4)^482=4!/.4 + 4!-√483=4!/.4 √.4 +√484= 44√4 -485=4!+4/.4 /.486=44√4 -√487=4x4! - 4/.488=44+4489=4!/√0.4 -0.4 /0.490=44√4 +√491=4x4! - √4/.492=44√4+493=4!x4 - √4/√.494=(√4/.4)! -4! -√495=4/.04 - √4/.496=4/.04 - √4/.497=4x4!+4/498=(√4/.4)! +√499=4x4! + √4 / √.4100=4(4!) +√4+√4Read more: What_are_the_answers_to_the_four_fours_questions_from_1-100


How do you get numbers 1-20 using 4 fours?

1 = 44 / 442 = 4 * 4 / (4 + 4)3 = (4 + 4 + 4) / 44 = 4 + (4 * (4 - 4))5 = (4 + (4 * 4)) / 46 = 4 + ((4 + 4) / 4)7 = (44 / 4) - 48 = 4 + 4 + 4 - 49 = 4 + 4 + (4 / 4)10 = (44 - 4) / 411 = (4 / 4) + (4 / .4)12 = (4 + 44) / 413 = 4 + ((4 - .4) / .4)14 = (4 * (4 - .4)) - .415 = 4 + (44 / 4)16 = (44 - 4) * .417 = (4 * 4) + (4 / 4)18 = (44 * .4) + .419 = (4 + 4 - .4) / .420 = 4 * (4 + (4 / 4))


How do you get the number 17 by only using the number 4?

(4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4) / 4 = 17


How do you make the numbers 0-50 using only four 4s?

0 = 44-44 1 = 44/44 or (4+4)/(4+4) or (4/4) / (4/4) 2 = 4/4+4/4 3 = (4+4+4)/4 4 = 4*(4-4)+4 5 = (4*4+4)/4 6 = 4*.4+4.4 7 = 44/4-4 8 = 4+4.4-.4 9 = 4/4+4+4 10 = 44/4.4 11 = 4/.4+4/4 12 = (44+4)/4 13 = 4-44/4 14 = 4*(4-.4)-.4 15 = 44/4+4 16 = .4*(44-4) 17 = 4/4+4*4 18 = 44*.4+.4 19 = 4!-4-4/4 20 = 4*(4/4+4) 21 = (4.4+4)/.4 22 = 44*sqrt(4)/4 23 = (4*4!-4)/4 24 = 4*4+4+4 25 = (4*4!+4)/4 26 = 4/.4+4*4 27 = 4-4/4+4! 28 = 44-4*4 29 = 4/.4/.4+4 30 = (4+4+4)/.4 31 = (4!+4)/4+4! 32 = 4*4+4*4 33 = (4+4! 34 = 44-4/.4 -6736 = 44-4-4 37 = (sqrt(4)+4!)/holy(4)+4! 38 = 44-4!/4 799740 = 44-sqrt(4*4) 42 = sqrt(4)+44-4 43 = 44-4/4 797945 = 4/4+44 46 = 44-sqrt(4)+4 47 = 4!+4!-4/4 48 = 4*(4+4+4) 49 = (4!-4.4)/.4 50 = 4!/4+44 52= (4!*4)-44 58= (sqrt(4)*(4!+4))+sqrt(4) 72= (4!*4)-4!*4o (small zero uptop four to the zero power = 1)


How do you find at least 6 math equations using only 6 fours to make it equal any prime number in between 1-100?

The primes required are: 2 = (4+4)/4 3 = (4+4+4)/4 5 = (4+4+4+4+4)/4 7 = (4*4+4+4+4)/4 11 = (4(4*4-4)-4)/4 13 = (4*(4*4-4)+4)/4 17 = (4*4*4+4)/4 19 = (4*(4*4+4)-4)/4 23 = (4*(4*4+4+4)-4)/4 29 = (4*(4*4+4+4+4)+4)/4 31 = (4*4*(4+4)-4)/4 37 = (4*4*(4+4)+4*4+4)/4 41 = (4^4-4*(4*4)+4)/4 43 = (4^4-4(4*4+4+4))/4 47 = (4^4-4*4*4-4)/4 The remainder are left as an exercise. It should be noted that most of these are impossible to express with only six fours without either defining new operators or allowing for facetious, unmathematical cheats such as allowing 44 to be used.


How do you get 4 using 4 fours?

√4 × √4 + 4 - 4 = 4 √4 × √4 × 4/4 = 4


What is 4 4 4 4 4 4 4 4 4 4 4 4 4 2?

54 104 it is.


How do you create equations for the numbers 1-10 using 4s for each with out the square root?

1 = 4/4 2 = (4 + 4)/4 3 = (4 + 4 + 4)/4 4 = 4 5 = 4 + 4/4 6 = 4 + (4 + 4)/4 7 = 4 + (4 + 4 + 4)/4 8 = 4 + 4 9 = 4 + 4 + 4/4 10 = 4 + 4 + (4 + 4)/4


How do you make the numbers 11-20 with four 4's only?

0 = [4 + 4 - (4 + 4)] 1 = [(4 + 4) / (4 + 4)] 2 = [4 * 4 / (4 + 4)] 3 = [(4 + 4 + 4) / 4] 4 = [4 + 4 - √4 - √4] 5 = [√4 + √4 +(4/4] 6 = [4 + √4 + 4 - 4] 7 = [4 * √4 - 4/4] 8 = [4 + 4 + 4 - 4] 9 = [4 + 4 + {4/4}] 10 = [44 - 4/4] 11 = [4!/√4 - 4/4] 12 = [4 * 4 - √4 - √4] 13 = [4! / {√4 + 4/4] 14 = [4 + 4 + 4 + √4] 15 = [4 * 4 - 4/4] 16 = [4 * 4 + 4 - 4] 17 = [4 * 4 + 4/4] 18 = [4 * 4 + 4 - √4] 19 = [4! - 4 - 4/4] 20 = [{4 * 4} + √4 + √4] Sorry if u wanted an answer not using ! or √ but I haven't figured them out yet though I only need 4 more which are 13, 14 ,18 and 19 if u know the equations for any one of them then please tell me. And also if you need others not including ! or √ which r between 0 to 20 than tell me I'll tell ya


How do you make 6 4's equal to 10?

10 = 4 + 4 + 4/4 + 4/4 10 = (4*4+4) * 4 / (4+4) 10 = (4+4) * (4+4/4) / 4 Variants of the problem: - with five 4's 10 = 4 + 4 + (4+4)/4 - with four 4's 10 = (4 + 4/4) * sqrt (4) - with three 4's 10 = 4 + 4 + sqrt (4)


How do you represent all of the integers from 0 to 100 by relating exactly four 4's together with mathematical symbols?

I'll start it, but I'm not going to finish it! 4 X 4 / 4 - 4 = 0 44 / 44 = 1 4 / 4 + 4 / 4 = 2 (4 + 4 + 4) / 4 = 3 (4 / 4)4 X 4 = 4 (4 / 4)4 + 4 = 5 (4 + 4) / 4 + 4 = 6 44 / 4 - 4 = 7 4 + 4 + 4 - 4 = 8 4 / 4 + 4 + 4 = 9 (44 - 4) / 4 = 10 (44 + 4) / 4 = 12 4! - 44 / 4 = 13 4! / 4 + 4 + 4 = 14 44 / 4 + 4 = 15 4 + 4 + 4 + 4 = 16 4 X 4 + 4 / 4 = 17 4 / √4 + 4 * 4 = 18 4! - 4 + 4 - 4 = 20 4! / 4 + 4 X 4 = 22 4 X 4 + 4 + 4 = 24 44 - 4 * 4 = 28 (4 + 4 / 4)! / 4 = 30 44 / (4 + 4) = 32 4! + 44 / 4 = 35 4! X 4! / 4 / 4 = 36 44 - 4 / √4 = 42 44 - 4 / 4 = 43 44(4/4) = 44 4 / 4 + 44 = 45 44 + 4 / √4 = 46 (4 + 4 + 4) X 4 = 48 √4 * 4 + 44 = 52 4 X 4 X 4 - 4 = 60 44 / 4 - √4 = 62 4(4 - 4/4) = 64 44 / 4 + √4 = 66 4 X 4 X 4 + 4 = 68 4! X 4! / (4 + 4) = 72 (4 X 4 + 4) X 4 = 80 (4 - 4 / 4)4 = 81 √4 * 44 - 4 = 84 √4 * 44 - √4 = 86 44 + 44 = 88 √4 * 44 + √4 = 90 √4 * 44 + 4 = 92 4! X 4 / 4 X 4 = 96


How do you play Pokemon music for harmonica?

Key of C: On The Road Far from Home 4 4 3 4 4 3 -4 -4 3 3 -4-4 3 3 5 -4 4 -4 5 4 -4 -4 5 -4 4 5 -4 4 -3 4 4 4 3 4 -4 -4 5 -4 4 5 -4 4 6 -4 4 4 4 5 -4 4 -4 4


How do you make the numbers 11-20 using four 4's?

11 = (42 - 4) - (4 / 4) 12 = (4 + 4) + (√4 + √4) 13 = (42 - 4) + (4 / 4) 14 = (4 + 4 + 4 + √4) 15 = (4 * 4) - (4 / 4) 16 = (4 + 4 + 4 + 4) 17 = (42 + √4) - (4 / 4) 18 = (42 + 4) - (4 - √4) 19 = (42 + 4) - (4 / 4) 20 = (4 * 4) + (√4 + √4)


How do you make the number 1-20 using only 4 4s with the simplest of equations?

I am doing the same thing. I only have answers with the square root thing on it sorry! Maybe you will be allowed it though :S 0 = (4 + 4) - (4 + 4) 1 = (4 + 4) / (4 + 4) 2 = (4 x 4 ) / (4 + 4) 3 = (4 + 4 + 4) / 4 4 = 4 + 4 - √4 - √4 5 = √4 + √4 + {4/4} 6 = 4 + √4 + 4 - 4 7 = 4 x √4 - {4/4} 8 = 4 + 4 + 4 - 4 9 = 4 + 4 + {4/4} 10 = 4 + 4 + 4 - √4 11 = 4 / {√4 - (4/4)} 12 = {4 x 4} - √4 - √4 13 = 4! - {√4 + (4/4)} 14 = 4 + 4 + 4 + √4 15 = {4 x 4} - {4/4} 16 = {4 x 4} + 4 - 4 17 = {4 x 4} + {4/4} 18 = {4 x 4} + 4 - √4 19 = 4! + 4- (4/4) 20 = {4 x 4} + √4 + √4 Sorry about the highlighting ... if it actually shows up??? ! mean to the power of 2. / means divide. Hope it helps it doesn't help me... :) :S :(


How do you make the numbers 1-10 with four 4's using BODMAS?

Here is one set of solutions. The answers here are not unique. 1 = (4*4)/(4*4) 2 = 4/4 + 4/4 3 = (4+4+4)/4 4 = (4-4)*4 + 4 5 = (4*4 + 4) / 4 6 = 4 + (4+4)/4 7 = 4 + 4 - 4/4 8 = 4 + 4 + 4 - 4 9 = 4 + 4 + 4/4 10 = (44 - 4)/4


How do you create equations for the numbers 1-10 using four 4s for each?

I've worked out some of them (/ is divide)(4/4) x (4/4)=1(4/4)+(4/4)=2(4 + 4+4)/4 = 3(4+4)x4+4=4(4 x 4 +4) / 4 = 54+((4+4)/4)=6(4+4)-(4/4)=7(4+4)/(4/4)=84+4+(4/4)=94 + 4 + 4 −√4=10


How many different combinations of four 4s make 2?

4/4 + 4/4 = 2 (one) 4 - (4+4)/4 = 2 (two) (4*4)/(4+4) = 2 (three) 4*(4/(4+4)) = 2 (four) ((4+4)/4) mod 4 = 2 (five) 4 + √4 - √4 - √4 = 2 (six) ((√4)/(√4)) + ((√4)/(√4)) = 2 (seven) 4 + 4 - 4 - √4 = 2 (eight) (√4)^4 / (4+4) = 2 (nine) (√(4*4)) / (4+4) = 2 (ten)