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Q: What is the divisors of 21?

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1,3,7, and 21

The divisors of 21 are: 1, 3, 7, 21.

The divisors of 147 are 1, 3, 7, 21, 49, 147.

The divisors of 42 are 1, 2, 3, 6, 7, 14, 21, 42.

There are 8 divisors of 105 (viz: 1, 3, 5, 7, 15, 21, 35, 105)

1, 3, 7, 9, 21, 63.

Eight. The odd divisors of 756 are: 1, 3, 7, 9, 21, 27, 63, 189.

First, you want to know the definition of a perfect number: A perfect number is an integer which is equal to the sum of all its positive integer divisors that are less than itself. Example: The positive integer divisors of 6, less than 6, are 1, 2, and 3. The sum of those divisors is 1 + 2 + 3 = 6. Therefore, 6 is a perfect number. Now, 21 does not meet this definition and therefore is not a perfect number. Let's try it. There are three positive divisors of 21, namely, 1, 3, and 7, that are less than 21, itself. (There are no others.) But the sum of these divisors is 1 + 3 + 7 = 11, which is not equal to 21. Therefore, we confirm that 21 is not a perfect number.

1, 3, 7, 9, 21, 63

1, 3, 7, 9, 21, 63.

1, 3, 7, 17, 21, 51, 119, 357.

1, 2, 3, 6, 7, 14, 21, 42.

1, 2, 3, 6, 7, 14, 21, 42.

The single-digit divisors of 3,456 are: 1, 2, 3, 4, 6, 8 and 9.

The divisors of 63 are: 1, 3, 7, 9, 21, 63.

1, 3, 7, 11, 21, 33, 77, 231.

1, 2, 3, 6, 7, 14, 21, 42.

The divisors of 147 are 1, 3, 7, 21, 49, and 147.These do: 1, 3, 7, 21, 49, 147.

It is a number for which the sum of the proper divisors is less the the number. Example: 21 has divisors 1, 3, and 7. The sum is 11 which is less than 21. Note: All prime numbers are deficient and as there are an infinite number of them, there are an infinite set of deficient numbers too.

It is deficient: It's only proper divisors are 1, 3, and 7, which sums to 11, which is less than 21.

1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

2,4,8 (1 and 16 are divisors too, but the number and 1 are always divisors)

293 only has two divisors because it is a prime number. The divisors are 1 and 293.

Divisors are used to divide numbers.

2,835 has 20 divisors.