x2-10x = 0
x(x-10) = 0
x = 0 or x = 10
If you mean: -10x-10y = -20 then x intercept is at (2, 0) and y intercept at (0, 2)
x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
"10x - x" is basically 10 x's minus one x. The answer is 10 minus 1, but in terms of x. Since 10 minus 1 is 9, the answer is 9x.
If you mean: -10x-10y = -20 then x intercept is at (2, 0) and y intercept at (0, 2)
10x=x 9x=0 x=0
x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.
x=-1.6
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
3x - 12 = 10x - 15 - 6x -10 3x - 12 = 4x -25 3x + 13 = 4x 13 = 4x - 3x 13 = x None?
7x + 8 = 10x - 2 ∴ 3x = 10 ∴ x = 10/3
X2 + 10X - 13 = 17 add 13 to each side X2 + 10X = 30 halve the linear coefficient ( 10 ), square it and add it to both sides X2 + 10X + 25 = 30 + 25 factor on the left and gather terms on the right (X + 5)2 = 55 (X + 5)2 - 55 = 0 ---------------------------vertex form, (- 5, - 55 ), is the vertex -------------------------------------------[-------------------------------]
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
0
x=0
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10