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Sorry, but it is impossible to solve this equation by itself. Since you have two unknowns, you need two equation.
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If 4y plus 9 equals 17 what does y equal?
y = 2 (4X2=8) +9 = 17
What is the length of one side of this square 4x2 - 4xy plus y2?
4x2 - 4xy + y2 = (2x - y)2 so the length of the side of the square must be 2x-y.
How do you factor 4x2 -y2-6y-9?
It is (2x +y + 3)*(2x - y - 3).
Find vertex and roots of y equals 4x squared plus 6?
y = 4x2 + 6 ory = 4x2 + 0x + 6, where a = 4, b = 0 and c = 6x-coordinate of the vertex = -b/2a = -0/2(4) = 0y-coordinate of the vertex = 4(02) + 6 = 6vertex is (0, 6)(Or you can say: Since the vertex of y = x is (0, 0), and this graph is shifted 6 units upward in the y-axis, then the vertex of y = x + 6 would be (0, 0 + 6) or (0, 6)Substitute 0 for y in order to find the roots.y = 4x2 + 60 = 4x2 + 60 - 6 = 4x2 + 6 - 6-6 = 4x2-6/4 = 4x2/4- 6/4 = x2± √(-6/4) = x± [√(6/4)]i = x x = [(1/2)√6]i or x = - [(1/2)√6]i
What is the vertex form of y -4x2-6x?
The question does not contain an equation: only an expression. An expression cannot have a vertex form.
If 4y plus 9 equals 17 what does y equal?
y = 2 (4X2=8) +9 = 17
How do you factor 4x2 - y2?
4x2-y2 = (2x-y)(2x+y)
How do you write 4x2 plus y equals 16 using function notation?
First you need to solve for y. So write 4x2+y=16 so y=16-4x2 Now write f(x)=16-4x2
Y equals 4X2 plus 3x plus 8?
y=4x2+3x+8
What is the range of the function y -4x2 1?
y = -4x2 + 1 Range = {y:y=<1, y is an element of the reals}
How does the graph of y 4x2 compare to the graph of y x2?
Their noses are both at the origin, and they both open upward, but y=4x2 is a much skinnier parabola.
What is 4x2 equal?
8
What is the range of the equation y 4x2 - 8?
y > -8
What is the square root of -4x2?
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
How is the graph of y 4x2 1 different from the graph of y 4x2?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Assuming the first function is y = 4x2 + 1, and the second y = 4x2 then the first graph is 1 unit higher than the second.
Is y equals 4x a quadratic equation?
No. [ y = 4x2 ] is a quadratic equation.
What does 4x2 plus 3 equal?
11
