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Q: What is the nth term of this sequence -2 -9 -16 -23 -30?

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The sequence is 2 larger than the 7 times table. The nth term can be expressed as 7n + 2.

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

58

It is: 27-2n

5, 11, 17, 23, 29

35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1

The nth term is 3(n+1). The twenty-third term is equal to 3 x (23 + 1) = 72

the equation that defines this sequence is nx = (n+(7+4(x-1))) (where x is the position of the term in the sequence (that is position 1 is 12, position 2 is 23 etc..)

All you have to do is add 5 each time(x+5) It's 43

Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.

The nth term is 7n-5 and so the 6th term will be 37

If you're asking what the nineth erm is, it's 58. The pattern is to add 7 to a umber to get the next number. 2+7=9, 9+7=16, 16+7=23, and so on.

2n +29

If you meant: 2 12 22 32 then the nth term = 10n-8

the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps

Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...

The differences are 3, 5, 7, 9,11, ... and the first term is -1; the nth term is: n² - 2

It is: 5n+3 and so the next term is 28

It is: 10n-7 and so the next term is 43

It is: 9n+5 and so the next term is 50

tn = n2 + 7