The lengths of the base and the side. You would multiply these to get the area and would double sum of the two to obtain the perimeter measurement.
you need length and width length multiply width = area length + length + width + width = perimeter
square
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
anything imaginary but a real shape would be a square or rectangle.
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
you need length and width length multiply width = area length + length + width + width = perimeter
The area of rectangle is : 56.0
square
NO, because if you did it would be a square
If you're trying to measure the perimeter of almost any shape like a square or triangle or octagon, simply count all the unit measurements of each side and add them together. If the unit your measuring is unknown, then leave it as units. For example, if you were finding the perimeter of a rectangle that has the measurements 6units, 6units, 4units, and 4units, the perimeter would be 20units. I hope this helped :)
If it was a square, which is a rectangle, the perimeter would be 24 meters . But it was a regular rectangle than it could be a few things actually , one of them would be 26 meters . Another would be 40 meters I think .
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
anything imaginary but a real shape would be a square or rectangle.
There is no single answer to that The rectangle could be 0.9 by 1, giving a perimeter of 2x(0.9+1)=3.8 Or it could be 0.45 by 2, giving it a perimeter of 2x(0.45+2)=4.9 The minimum perimeter is when it is a square. The square root of 0.9 is approx 0.94868, so the perimeter would be approx 3.7947
In the case of a rectangle, you would maximize the area given the perimeter by making the dimensions equal. In other words, you would make the rectangle into a square. However, to truly maximize the area, you would make the perimeter a perfect circle.
Yes it measures 3 on all sides sides across from each other but it would have to be a square. Having a rectangle is impossible. Then again a square is a rectangle but a rectangle isn't a square.
If it was a square, the answer would be 81 square cm. The area will be the product of two numbers whose sum is half the perimeter.