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Q: Which is a factor of 6a2 5ab - 6b2?

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6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)

6a2 + 5ab - 6b2 = 6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)*(3a - 2b)

Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).

(5ab^2 + 4cd)(5ab^2 4cd) <

The GCF of 5ab and 56b squared is b.

b2(b + 6)

-3b2(5b - 2)

3(2b2 - 5b - 2)

(-3b - 4)(-2b + 5)

5ab(3a - 2b)

8(8 - 5ab)

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(2a - 1)(3a + 4)

6a2

The GCF of 6a^2 and 8a is 2a.

55/5ab + 4/5ab = 59/5ab

7ab-5ab = 2

gcd of 5ab,28xy

6b^2-13bs-63s^2 is factorised to (2b-9s)(3b+7s)

(5ab)2 = 25a2b2 (provided a and b are elements of a commutative group).

5 - a - 1 + c - 6a2 + a2

The given polynomial does not have factors with rational coefficients.

1.25

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