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Allene Morissette
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∙ 3y agoThis answer is:
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∙ 10y agoThere are no two real numbers that do, but the two complex numbers:
(-3/2 + i√31/2) and (-3/2 - i√31/2) do.
Multiplying to -10 (negative ten) and summing to -3 (negative three) is solved by the real numbers -5 and 2.
Multiplying to -10 (negative ten) and summing to 3 (positive three) is solved by the real numbers 5 and -2.
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