90 (90/6= 15; 90/5= 19)
In order to be divisible by both 2 and 3, a number must be divisible by 6.The largest multiple of 6 less than 100 is 96 ... the 16th multiple of 6.So there are 16 of them.
The number is 90.
90
The anwer is 90 ,90 divided 6 is 15 and 90 divided by 5 is 18.
To be divisible by both 4 and 5, the number has to be divisible by 20. Therefore, there are 12 numbers between 1 and 240, inclusive, which are divisible by 4 and 5: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240.
The total number of integers between 100 and 300 that are divisible by three is 66.
1900
Just 1.
36 and 72 both are.
In order to be divisible by both 2 and 3, a number must be divisible by 6.The largest multiple of 6 less than 100 is 96 ... the 16th multiple of 6.So there are 16 of them.
The number is 90.
0,12,24,36,48,60,72,84, and 96 are the numbers between 0 and 100 that are divisible by both 3 and 4.
105
251
It is 90.
90
The anwer is 90 ,90 divided 6 is 15 and 90 divided by 5 is 18.