Q: What number can go into 12 and 63?

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1 and 3 can go into 12 and 63.

75

63 - 3 = 60 = 5 x 12 12 times with 3 remaining

There are an infinite number of them. The smallest one is 63, and the rest are all the multiples of 63.

The number 3 can go in to 63 21 times. 63 divided by 3 equals 21.

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1 and 3 can go into 12 and 63.

51

75

-12 + 75 = 63 So if minus 12 is increased by 75 the new number is 63 If the question was 75 percent, the number would be 36.

Nine will go into 63 seven times.

12 with 3 remaining 63 - 3 = 60 = 5 x 12

To find the largest number that, when divided into both 63 and 75, leaves a remainder of three, you can use the concept of greatest common divisor (GCD) or greatest common factor (GCF). The GCD of 63 and 75 is the largest number that can evenly divide both numbers. To find it, you can use the Euclidean algorithm: Start with the two numbers: 63 and 75. Divide 75 by 63: 75 ÷ 63 = 1 with a remainder of 12. Now, replace the larger number (75) with the remainder (12) and keep the smaller number (63) as is: 63 and 12. Repeat the process: 63 ÷ 12 = 5 with a remainder of 3. Again, replace the larger number (63) with the remainder (3) and keep the smaller number (12) as is: 12 and 3. Repeat once more: 12 ÷ 3 = 4 with no remainder. Now that you have reached a point where the remainder is 0, the GCD is the last non-zero remainder, which is 3. So, the largest number that, when divided into both 63 and 75, leaves a remainder of three is 3.

Seven goes into both 63 and 77

3 = 63/21 = 150/50

63 - 3 = 60 = 5 x 12 12 times with 3 remaining

It is 1

There are an infinite number of them. The smallest one is 63, and the rest are all the multiples of 63.