There are infinitely many sequences that start with 1, 8, 29, 92. However, the simplest answer is 281. Each term is generated by multiplying the previous term by 3 and adding 5.
The first 10 numbers in the sequence are: 1, 8, 29, 92, 281, 848, 2549, 7652, 22961, 68888
42 is the next number in this sequence. This number sequence is adding the next prime number to the last number. So 1 + 2 = 3. Then 3 + 3 = 6, 6 + 5 = 11, 11 + 7 = 18, 18 + 11 = 29. The next prime number after 11 is 13, so 29 + 13 = 42. The next numbers would be 59 (42+17), 78 (59+19), and 101 (78+23)
It looks like it is +6, -5, +12, -5. So I would assume the next number is +18, or 29.
These are just the first prime numbers. The next few are 13, 17, 19, 23, 29, 31...
35
21
42 is the next number in this sequence. This number sequence is adding the next prime number to the last number. So 1 + 2 = 3. Then 3 + 3 = 6, 6 + 5 = 11, 11 + 7 = 18, 18 + 11 = 29. The next prime number after 11 is 13, so 29 + 13 = 42. The next numbers would be 59 (42+17), 78 (59+19), and 101 (78+23)
127.
16 21 22 29
It looks like it is +6, -5, +12, -5. So I would assume the next number is +18, or 29.
38 20+3 = 23 23+6=29 29+9=38
These are just the first prime numbers. The next few are 13, 17, 19, 23, 29, 31...
11, 16, 22, 29, 37, 46...
29, assuming it is an algebraically reclusive sequence.
29
One possibility: -3
58
35