220 goes into 64 zero times, since it is the larger number. 64 can go into 220 exactly 3.4375 times (3 remainder 28).
The only common factor of 49 and 64 (whole number that goes into both of them evenly) is ' 1 '.
64/4=16
2 is a number which goes into both.
64% of 28= 64% * 28= 0.64 * 28= 17.92
220 goes into 64 zero times, since it is the larger number. 64 can go into 220 exactly 3.4375 times (3 remainder 28).
(28 + 64)/2 = 92/2 = 46(28 + 64)/2 = 92/2 = 46(28 + 64)/2 = 92/2 = 46(28 + 64)/2 = 92/2 = 46
28 is the non-cubic number The others work out like this - 2x2x2=8 4x4x4=64 5x5x5=125
The only common factor of 49 and 64 (whole number that goes into both of them evenly) is ' 1 '.
2 is one such number.
The HCF of 16 and 64 is 16
64/4=16
64% of 28= 64% * 28= 0.64 * 28= 17.92
2 is a number which goes into both.
2 goes evenly into 4 and 28
The only common factor of 343 and 64 is 1.
This problem can be solved by substituting (x) for the unknown number and (x + 28) as the number that is 28 more than the unknown number. Set up and solve the problem: x + (x + 28) = 156 (then simplify): 2x + 28 = 156 (subtract 28 from both sides of the equation to isolate the known numbers from the unknown): 2x = 128 (divide both sides by 2 to find the value of x) x (the unkown number) = 64 (now use the value of x to prove the answer) 64 + (64 + 28) = 64 + 92 = 156