9 tens + 12 ones = 9 × 10 + 12 × 1 = 90 + 12 = 102.
129
The value of 9 would be hundreds in this question the 4=thousands 9=hundreds 6=tens 2=ones
9 units or 9 ones - which is 9.
If the first digit is 9, you have 9 options (0-8) for the second digit. If the first digit is 8, you have 8 options (0-7) for the second digit. Etc. This leaves you with the arithmetic series: 0 + 1 + 2 + 3 + ... + 9.
I think the answer is 612!1 (tens digit) which is odd is half of 2 (hundreds digit) and the sum is (6+1+2=9).
It is not possible to say without knowing what the numbers are. The digits could become smaller, larger or remain the same. 52 - (-11) = 63 (both larger) 52 - (-10) = 62 (tens larger, units same) 52 - (-9) = 61 (tens larger, units smaller) 52 - (-1) = 53 (tens same, units larger) 52 - 0 = 52 (both same) 52 - 1 = 51 (tens same, units smaller) 52 - 9 = 43 (tens smaller, units larger) 52 - 10 = 42 (tens smaller, units same) 52 - 11 = 41 (both smaller).
What number has 9 tens and 4 fewer ones than tens
99
99
9 tens = 90. 4 fewer ones than tens = 9 - 4 = 5. Therefore the answer is 95.
95
709
The number you are looking for is 74.
0.4111567111203111789
1249
ask me
If you have 6 hundreds 3 ones 14 tens and 9 tenths, you are 743.9.
Do it one piece at a time. Seven tens is 70. Nine ones is 9.Now add 70 + 9 and you get 79.