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Q: What number is divisible by 2 and 3 but not 9?

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To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

no because to be divisible by 9 the number has to equal 9 for instance 2+9+3+8=22 so it is not divisible by 9. But 32121 3+2+1+2+1=9 so it is divisible by 9

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.

If a number is even, it's divisible by two. If the digits of a number add up to a multiple of 3, it's a multiple of 3. For example, 342 is divisible by 3 because 3 + 4 + 2 = 9 and 9 is divisible by 3.

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9. 26 is divisible by 2 but not divisible by 3, 5 nor 9.

Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.

yes, you know that because if you add the digits together and that number is divisible by 9, then that large number is divisible by 9. 3+4+2 is 9, which is divisible by 9. conclusion 342 is divisible by 9.

If a number is not divisible by 3 then it is not divisible by 9.

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.

180 is divisible by 2, 3, 4, 5, 9, and 10.

no, it comes out to a decimal number so that means it is not divisibleTo check if a number is divisible by 6 it must be divisible by both 2 and 3.To check if a number is divisible by 2, if the last digit is even (ie one of 0, 2, 4, 6, 8) it is divisible by 2. Last digit is 0, so it is divisible by 2.To check if a number is divisible by 3, add all the digits together and if the sum is divisible by 3 so is the original number. This can be repeated on the sum until a single digit remains in which case if it is 3, 6 or 9 then the original number is divisible by 3.7960 → 7 + 9 + 6 + 0 = 22 (not divisible by 3 - know, or:)22 → 2 + 2 = 4 (not 3, 6, 9 so not divisible by 3)So 7960 is not divisible by 3, so 7960 is not divisible by 6.

add all the digits of the number and check if it is divisible by 3. eg-3321=3+3+2+1=9=divisible by three.the same works for 9.

The least number divisible by 2, 3, 4, 5, 6, 9, and 10 is 180.

Yes, every number that's divisible by 9 is divisible by 3

A prime number is not divisible by any numbers except 1 and itself. A composite number is divisible by other numbers. 9 is divisible by 3, so it is a composite number.

Yes, any number divisible by 9 is also divisible by 3.

No. To find whether the number is divisible by 3, you add each digits and if it's equal to 9 then it's divisible by 3 because 9 is divisible by 3. 9 + 8 + 2 = 19, 1 + 9 = 10... so it's not divisible by 3.

896 is only divisible by 2; it is not divisible by 3, 5, 9 nor 10. To be divisible by 2, the number must be even, ie, the last digit must be even, that is one of {0, 2, 4, 6, 8}; 896 ends in 6 which is even, thus 896 is divisible by 2. To be divisible by 3, add the digits of the number together and if the sum is divisible by 3, then so is the original number. The test can be repeated on the sum until a single digit remains; if this single digit is 3, 6, or 9 then the original number is divisible by 3: 896 → 8 + 9 + 6 = 23 → 2 + 3 = 5 which is not one of {3, 6, 9}, thus 896 is not divisible by 3 To be divisible by 5, the last digit must be 0 or 5; 896 ends in 6 which is neither 0 nor 5, so 896 is not divisible by 5. To be divisible by 9, add the digits of the number together and if the sum is divisible by 9, then so is the original number. The test can be repeated on the sum until a single digit remains (which is called the digital root of the number); only if this single digit is 9 will the original number be divisible by 9: 896 → 8 + 9 + 6 = 23 → 2 + 3 = 5 which is not one 9 thus 896 is not divisible by 9; To be divisible by 10 the last digit must be 0; 896 ends if 6 which is not 0, so 896 is not divisible by 10.

For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.

Any number which is divisible by 9 contains digits which, when added together, are equal to 9 or a multiple of 9. For example, 63 is divisible by 9 because 6 + 3 = 9. 288 is divisible by 9 because 2 + 8 + 8 = 18 and 18/9 = 2.

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