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Absolutely not! If it is divisible by 9 it must be divisible by 3.

Here, if you want it, is a proof:

x is divisible by 9 implies that x = 9*y for some integer y.

Now 9 = 3*3, so writing 3*3 instead of 9 gives

x = (3*3)*y

so, by the associative property of multiplication,

x = 3*(3*y)

and then, by the closure of multiplication of integers, 3*y is also an integer. Say, z, for example.

That is to say, x = 3*z

which is equivalent to saying that x is divisible by 3.

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11y ago
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14y ago

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

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11y ago

Because any number that has 6 as a factor will also have the factors of 6 as factors.

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11y ago

Multiples of multiples of three are also multiples of three.

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10y ago

3, 6, 9, 12, 15 and just keep adding three until you get to infinity.

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7y ago

No. 5 and 7 are odd numbers.

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7y ago

The set of multiples of 9.

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9y ago

18

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3y ago

because three times one equals three

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72

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Q: What number is divisible by 3 6 and 9?
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Related questions

What is the smallest number divisible by 3 6 and 9?

The smallest number divisible by 3 6 and 9 is 18.


Is every number divisible by 3 and 9 is also divisible by 6 is this true?

No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6


Is 78 divisible by 6 and 9?

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.


Is 32643 divisible by both 3 and 9?

To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.


What largest 3 - digit number divisible by both 6 and 9?

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.


What is a greater number than 6 but divisible by 3?

9 is greater than 6 and divisible by 3.


Is 234 divisible by 3 6 and 9?

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.


How are the divisibility rules for 3 6 and 9 alike?

A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.


What is a number that is divisible by 2 and 3 but not 9?

6


Is a number divisible by three and nine also divisible by six?

No. For example, 9 is divisible by 3 and 9, but not 6. Even numbers that are divisble by 3 and 9 are also divisble by 6.


What is a 4-digit number that is divisible by only 6 and 9?

There is no number that is divisible by only 6 and 9 because any number is divisible by 1 and itself. Furthermore, any number that is divisible by 6 MUST be divisible by 2 as well as 3 - so only 6 is impossible.


Is the number 26 divisible by 2 3 5 or 9 How do you know?

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9. 26 is divisible by 2 but not divisible by 3, 5 nor 9.