All multiples of 525 (which are infinite) including 525, 1050, 1575, 2100, 2625 . . .
525 is divisible by 5, since it ends with a 5. 525/5 = 105 525 is not divisible by 2, since it does not end with 0, 2, 4, 6, or 8. 525/2 = 262.5
Yes, evenly
510
The multiples of 105 (which are infinite) are all divisible by 105, including these: 105, 210, 315, 420, 525, 630, 735, 840, 945 . . .
Yes, the result is 175.
525 is divisible by 5, since it ends with a 5. 525/5 = 105 525 is not divisible by 2, since it does not end with 0, 2, 4, 6, or 8. 525/2 = 262.5
525 is divisible by 5 (in addition to 1 and itself). It is a composite number.
Find the sum of the first hundred even natural number divisible by 5?
Yes, evenly
510
The multiples of 105 (which are infinite) are all divisible by 105, including these: 105, 210, 315, 420, 525, 630, 735, 840, 945 . . .
525 = 35 x 15
Yes.
Yes, the result is 175.
No. To find out if a number is divisible by 3, just add up the numbers and if that number is divisible by three then the whole number is. So, 5+3+5=13, so it is not divisible by three. 5+2+5=12, so 525 IS divisible by three. Pretty neat, huh?!
The list is infinite. Here are some of them: 210, 315, 420, 525, 630, 735, 840.
1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175, 525