The original set would be 107, 98, 90, 83, 77, x, 68, and 65. The pattern of this set of numbers is that the first term is subtracted by 9, the next by 8, the next by 7, and so on. Therefore, the term x would be 72, which is 5 less than 77 and 4 more than 68.
Not sure about completing the pattern since there is no reason for it to stop after the next number.
There is no polynomial solution for polynomials of order 5 of lower. The simplest answer is obtained by fitting the following polynomial of order 6:
U(n) = (4*n^6 - 155*n^5 + 1345*n^4 - 5825*n^3 + 13288*n^2 - 17060*n + 34080)/240 for n = 1, 2, 3, ...
107 98 90 83 77 __ 68 65
72.......107-98(9) 98-90(8) 90-83(7) 83-77(6) 77-[72](5) 72-68(4) 65
It is 107 - 7 = 100.
107
107/10
107 98 90 83 77 __ 68 65
It could be: 2*214 = 428
72.......107-98(9) 98-90(8) 90-83(7) 83-77(6) 77-[72](5) 72-68(4) 65
1 and 107 (107 is a prime number).
The number 107 is a "prime" number. That means that only the number 1 and the number itself will divide into it.
107 squared is 11449
107 is a prime number.
3.4 * 107 = 34,000,000, so anything greater than that works. In case you meant 107 and not 107, 3.4 * 107 = 363.8.
107 is a prime number but 117 is a composite number
9n-107. Where n is the chosen number .
107 is a prime number and is divisible only by 1 and 107.
107 is, itself, a prime number.