A probability density function.
1/12
There are 62 or 36 outcomes for rolling 2 dice. The outcomes that meet the criteria specified are: 1,6 2,6 3,6 4,6 6,4 6,3 6,2 6,1. So the probability of one die shows a 6 and the other is a number less than 5 is 8/36 or 2/9.
The probability of rolling a 6 on each roll of an unbiased cuboid die is 1/6 If you mean at least one of the rolls shows a 6 then it is the same as 1 - pr(no roll shows a 6) = 1 - (5/6)⁶⁰ ≈ 1 - 0.0000177 = 0.9999823 If you mean that exactly one 6 is rolled then: Pr(exactly one 6) = 60 × 1/6 × (5/6)⁵⁹ ≈ 0.0002130
The probability of rolling a 3 on each roll of an unbiased cuboid die is 1/6 If you mean at least one of the rolls shows a 3 then it is the same as 1 - pr(no roll shows a 3) = 1 - (5/6)⁶⁰ ≈ 1 - 0.0000177 = 0.9999823 If you mean that exactly one 3 is rolled then: Pr(exactly one 3) = 60 × 1/6 × (5/6)⁵⁹ ≈ 0.0002130
This is the same as 1 minus the probability that neither of them are greater than three. This is 1, minus the probability of getting greater than three, squared. Rolling higher than three has a 1/2 probability, so: P(at least one greater than 3) = 1 - (1/2)2 = 1 - 1/4 = 3/4
equation
expression
The probability of the event occurring.
The probability is 0.5
3
9+7