The number that both 7 and 8 can go into evenly is 56.
Only the number 1
3*(n + 8) = 21 Divide both sides by 3: n + 8 = 21/3 = 7 Substract 8 from both sides: n = 7 - 8 = -1
The number 7 goes into both 56 and 119 (56/7 = 8, 56/7 = 17).
49 over 56 - all you need to do is take both the top number and the bottom number and multiply them by the same number - what you get will always be equal to 7 over 8 - for the example I gave before, i multiplied both numbers by 7
The number that both 7 and 8 can go into evenly is 56.
7 and 8 both go into 56
Only the number 1
3*(n + 8) = 21 Divide both sides by 3: n + 8 = 21/3 = 7 Substract 8 from both sides: n = 7 - 8 = -1
The number 7 goes into both 56 and 119 (56/7 = 8, 56/7 = 17).
49 over 56 - all you need to do is take both the top number and the bottom number and multiply them by the same number - what you get will always be equal to 7 over 8 - for the example I gave before, i multiplied both numbers by 7
Let say that the number is xy, then y + x = 8 y - x = 6 add both equations; 2y = 14 divide by 2 to both sides; y = 7 7 + x = 8 substitute 7 for y to the first equation of the system, and subtract 7 to both sides; x = 1 The number is 17.
7 + 7^(7 - 7) = 8.
8/7 as a mixed number = 11/7
8 is a composite number but 7 is a prime number
The factors of 7 are 1 and 7.The factors of 8 are 1, 2, 4 and 8.1 is the only number that appears on both lists.
2x + 7 = 15 Subtract 7 from both sides: 2x = 8 Divide both sides by 2: x = 4