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Yes. The only known almost perfect numbers are the powers of 2. 32 = 2^5 is an almost perfect number. It has not yet been proved whether {x: x = 2^n for n in N} = {x: x is an almost perfect number}.
The prime numbers of 20 are 2, 2 and 5. (2*2*5 = 20)
5+5+5+5
The two numbers are 5 and 4. 5 x 4 = 20 5 + 4 = 9
As factors, 1 and 5
wht is parasite
Perfect numbers are numbers where all the factors add to that number. For example 6's factors are 1,2, and 3 and 1+2+3=6. Therefore the next perfect number isn't until 28 which is 1,2, 4, 7, 14 where 1+2+4+7+14= 28 An almost perfect number is a number which, when adding all of its proper divisors (all divisors except himself), gives you one less, or one more then the number itlself. Up to now all known almost perfect numbers are 2^n. So to answer your question, the 2 almost perfect numbers between 5 and 20 are 8 and 16. Divisors of 8: 1,2,4 -----> 1+2+4=7 Divisors of 16: 1,2,4,8 -----> 1+2+4+8=15
The only two are 9 and 16.
Yes. The only known almost perfect numbers are the powers of 2. 32 = 2^5 is an almost perfect number. It has not yet been proved whether {x: x = 2^n for n in N} = {x: x is an almost perfect number}.
Almost Perfect - 1995 Dating for Ratings 2-5 was released on: USA: 20 December 1997 Germany: April 1998
81. They are the perfect squares of numbers starting from 5.81. They are the perfect squares of numbers starting from 5.81. They are the perfect squares of numbers starting from 5.81. They are the perfect squares of numbers starting from 5.
5 and 2 are perfect numbers
No. The first two "perfect numbers" are 6 and 28.
The sum of -5 and 20 is 15. The distance between -5 and 20 is 25. The sum of the numbers between -5 and 20 is 180. The sum of the numbers from -5 to 20 is 195.
1,19,23,27,30 ( divided by ) 5= 20
The prime numbers of 20 are 2, 2 and 5. (2*2*5 = 20)
15504 different sets of 5 numbers in each. This is a combination of 5 from 20: 20C5 = 20!/(20-5)!5! = 20x19x18x17x16/5x4x3x2x1 = 15504.