Q: What is the sum of 1 plus 2 plus 3. plus 100?

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5050

303

The sum of the numbers up to 100 is equal to (100 x 101)/2 = 5050

1+1+2 = 4

Sum = 79*(79+1)/2 = 79*80/2 = 3160

if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;

2

2

1+2+4 = 7

Sum of numbers from 1 to 100:(1+100) + (2+99) + (3+98) + (4+97) + ... + (49+52) + (50+51) =50 pairs, each pair adds up to 101= (50 x 101)= 5,050

1 + 2 + 100 + 55 = 158

2 + 1 = 3

The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1

You add 1 plus another one and you get 2

It is 100*(100+1)/2 = 50500.

87

25

26

3

3

81*82/2= 3321

2*100 = 200 12*10 = 120 14*1 = 14 Sum = 334

100 + 99 + 98 + 2 + 1 + 0.3 = 300.3

Without just going and doing the addition, you can use this formula:Sum of 1 to N is: (N+1)*N/2. So take sum of [1 to 100], then subtract off the sum of [1 to 20], and you'll have left the sum [21 to 100].Sum [1-100] = (100+1)*100/2 = 5050. Sum[1-20] = (20+1)*20/2 = 210.So 5050 - 210 = 4840

1 plus 1

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