I guess you mean those numbers which are multiples of both 6 and 9.
The lowest common multiple of 6 and 9 is 18, so those numbers which are multiples of both 6 and 9 are the multiples of 18. The first 100 are:
18, 36, 54, 72, 90, 108, 126, 144, 162, 180, 198, 216, 234, 252, 270, 288, 306, 324, 342, 360, 378, 396, 414, 432, 450, 468, 486, 504, 522, 540, 558, 576, 594, 612, 630, 648, 666, 684, 702, 720, 738, 756, 774, 792, 810, 828, 846, 864, 882, 900, 918, 936, 954, 972, 990, 1008, 1026, 1044, 1062, 1080, 1098, 1116, 1134, 1152, 1170, 1188, 1206, 1224, 1242, 1260, 1278, 1296, 1314, 1332, 1350, 1368, 1386, 1404, 1422, 1440, 1458, 1476, 1494, 1512, 1530, 1548, 1566, 1584, 1602, 1620, 1638, 1656, 1674, 1692, 1710, 1728, 1746, 1764, 1782, 1800
I'll leave the rest of them to you (there are an infinite number of them).
The common multiples of 6 and 9 are infinite, starting with: 18, 36, 54, 72, 90, 108, 126, 144, 162, 180 +18 . . .
They are members of the infinite set of numbers of the form 18*k where k is an integer.
18, 36, 54, 72, 90
18, 36, 54 and so on.
18 and 36
18, 36, 54
42, and all multiples of 42.
Yes, for example the multiples of 2 are: 2, 4, 6, 8, 10, 12, 14, ......etc. (all even numbers are multiples of 2) or multiples of 3 are 3, 6, 9, 12, 15, 18, 21, ....... etc.
Any multiple of 18.
Multiples of 5,6 and 9 are 90, 180, 270, 360, 450 and so on. Multiples of 90 will all be multiples of 5, 6 and 9.
There are infinitely many multiples of 9 and 21 so it is impossible to list them. One of their multiples is 9*21 = 189.
The numbers 3,6 and 9 are all multiples of 3 because 3 can go into all of them evenly.
All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.
it is 18. 18 is a multiple of all three numbers. multiples of 3: 3,6,9,12,15,18... multiples of 6: 6,12,18... multiples of 9: 9, 18...18
No; all multiples are not multiples of 6, for example 3×3 = 9 is not a multiple of 6. However as 6 = 2×3 all multiples of 6 are also multiples of 3.
All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
This question is true
18 and multiples of 18.
3 yes, 6 no.
There is an infinite number of common multiples for 6 9 and 10. A common multiple of any two or more numbers is any number into which each of two or more numbers can be divided evenly (zero remainder). However, the least or lowest common multiple (LCM) of 6 9 and 10 is 90.
no take 3 for example. 3 6 9 3 x 3= 9 so that's composite.
Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.
18 and all the multiples of 18.