Your answers are 1 & 3
The only number that can divide by both 83 and 75 is one as 83 is a prime number and therefore only has 2 numbers that can divide by it anyway
2 divide 75
maybe divide 75 by 12
1 3 5 15 25 75.
6 factors
The only number that can divide by both 83 and 75 is one as 83 is a prime number and therefore only has 2 numbers that can divide by it anyway
You look for common factors, then divide both numbers by the common factor.
2 divide 75
12
Assuming you meant 12/75... the answer is 4/25 because both figures will divide by three exactly.
Well, isn't that just a happy little group of numbers we have there? To find the mean average, you simply add up all the numbers and then divide by how many there are. So, for these numbers, you would add 18 + 12 + 10 + 10 + 25, which equals 75. Then, you divide 75 by 5 (since there are 5 numbers), giving you a mean average of 15. Happy calculating!
The ratio of 15 to 75 can be simplified by dividing both numbers by their greatest common factor, which is 15. When we divide 15 by 15, we get 1, and when we divide 75 by 15, we get 5. Therefore, the ratio of 15 to 75 in lowest terms is 1:5.
maybe divide 75 by 12
1 3 5 15 25 75.
Divide by 12
The number that goes into both 75 and 100 equally is 25. This is because 25 is a common factor of both 75 and 100, meaning it can divide both numbers evenly without leaving a remainder. In mathematical terms, both 75 and 100 are divisible by 25.
To find the largest number that, when divided into both 63 and 75, leaves a remainder of three, you can use the concept of greatest common divisor (GCD) or greatest common factor (GCF). The GCD of 63 and 75 is the largest number that can evenly divide both numbers. To find it, you can use the Euclidean algorithm: Start with the two numbers: 63 and 75. Divide 75 by 63: 75 ÷ 63 = 1 with a remainder of 12. Now, replace the larger number (75) with the remainder (12) and keep the smaller number (63) as is: 63 and 12. Repeat the process: 63 ÷ 12 = 5 with a remainder of 3. Again, replace the larger number (63) with the remainder (3) and keep the smaller number (12) as is: 12 and 3. Repeat once more: 12 ÷ 3 = 4 with no remainder. Now that you have reached a point where the remainder is 0, the GCD is the last non-zero remainder, which is 3. So, the largest number that, when divided into both 63 and 75, leaves a remainder of three is 3.