3
GCF(52, 48) = 4
48
One and three.
1, 2, 3 and 6 all go into both 48 and 114 evenly.
The numbers that go into both 48 and 132 evenly are their common divisors. The greatest common divisor (GCD) of 48 and 132 is 12, meaning that the numbers that divide both evenly include 1, 2, 3, 4, 6, and 12. Other divisors for 48 are 8, 16, and 24, while for 132 they include 11, 22, 33, and 66. Thus, the common factors are 1, 2, 3, 4, 6, and 12.
GCF(52, 48) = 4
Itself and any other factors of 48
48
Because two goes into 48 evenly: 48 / 2 = 24
Yes, but not evenly. 24 goes into 84 3.5 times.
One and three.
1, 2, 3 and 6 all go into both 48 and 114 evenly.
The greatest common factor is the highest number that is a factor of both numbers (divides into them evenly). 24/24 = 1, and 48/24 = 2, so it's 24. 24 goes evenly into both numbers, and is definitely the greatest because it is the highest factor of 24.
The problem is to find the largest positive integer which goes evenly into the two given numbers.
1. Also 2. And finally 4.
1, 2, 3, 6.
HCF(42, 48) = 6 So the answer is 6 and all its factors.