105 is not a Prime number among them. It is because it is divisible by 5.
97 101 103
The prime numbers between 80 and 105 are: 83, 89, 97, 101, 103
Eleven numbers less than 105 are relatively prime to 105. They are 82, 83, 86, 88, 89, 92, 94, 97, 101, 103, and 104.
Assuming you meant 101, 103, 105 & 107... The number 105 is not prime - as it will divide by 5 or 3.
91, 97, 101, 103, 107, 113 so therefore i think it is 102 ([101 + 103] / 2 = 102) the average is 100.333 (all the Number / amount of number, in this case 602/6 = 100.3333) hope this help i done this in about 5 minutes in my head, so if i missed a prime number or something I'm sorry lolz sources: me :D:D:D
97 101 103
The prime numbers between 80 and 105 are: 83, 89, 97, 101, 103
89 97 101 103.
Eleven numbers less than 105 are relatively prime to 105. They are 82, 83, 86, 88, 89, 92, 94, 97, 101, 103, and 104.
The numbers 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101 and 103 are prime.
61, 67, 71, 73, 79, 83, 89, 97, 101 and 103.
For this type of question, you should search the Internet for a list of prime numbers. All the integers that are not prime numbers are composite. In this case, the relevant prime numbers are 101 and 103.
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Assuming you meant 101, 103, 105 & 107... The number 105 is not prime - as it will divide by 5 or 3.
The numbers are 101, 103 and 105.
91, 97, 101, 103, 107, 113 so therefore i think it is 102 ([101 + 103] / 2 = 102) the average is 100.333 (all the Number / amount of number, in this case 602/6 = 100.3333) hope this help i done this in about 5 minutes in my head, so if i missed a prime number or something I'm sorry lolz sources: me :D:D:D
101, 103, 107, 109 not 105 as that is divisible by 5