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Q: What numberwhen divided by 43 gives a quotient of 18 and a remainder of 27?

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The quotient is 47 with a remainder of 1

467 divided by 34 gives you a quotient of 13 and a remainder of 25.

0.1481

447

99

2351

10.102

200

236 divided by 5 is 47 with remainder 1

Yes, it can be , for example 9/5 gives you quotient=1 and remainder =4 and other case 16/5 gives you quotient =3 and remainder = 1

3 divided by 2 gives 1r1

49, when divided by 7, gives a quotient of 7

1.5625

According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.

I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1

-2

8

237 is a COMPOSITE number. Since it is divided by 3 and gives a quotient of 79 (which is a prime factor of 237) and remainder as 0.

8.

6.8571

23, 58, 93, 128, 163, 198, ...

12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.

Nope. 22 divided by 7 is 3 with remainder 1.

The quotient of 95 divided by 5 is 19

35 - 18 = 17 17/n = 20 n = 17/20 = 0.85