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A Pentagon has an interior angle of 108 degrees.

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Q: What polygon has an interior angle of 108 degrees?
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How many side are there in a polygon if one of the interior angles measures 108?

A polygon with any number of sides can have an interior angle measuring 108 degrees.


An interior angle of a regular polygon is found to be 108 degrees What is the regular polygon called?

Obtuse


What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?

The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.


What is a polygon called if each interior angle is 108 degrees?

A [regular] pentagon.


What is the mesure of an interior angle of a regular polygon of five sides?

108 degrees


What is the measure of an interior and an exterior angle of a regular polygon with 5 sides?

Each exterior angle: 72 degrees Each interior angle: 108 degrees


If the exterior angle of a regular polygon is 108 degrees how many sides does the polygon have?

That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.


How many sides does a regular polygon have if each exterior angle is 2520 degrees?

An exterior angle of 2520 degrees is impossible. Assuming you mean 252 degrees, this would make each interior angle 108 degrees, as 360- 252 = 108. A regular polygon with 108-degree interior angles has 5 sides, or in other words, it is a regular pentagon.


If the interior angle of a polygon is 108 how many sides does the polygon have?

In general, this question cannot be answered. Any polygon can have an interior angle of 108 degrees. For example, a triangle with angles of 108, 32 and 40 degrees; or a quadrilateral with angles of 108, 72, 90 and 90 degrees and so on.In the rare event that the polygon is a regular polygon, then suppose it has n sides.The sum of its interior angles is then (n-2)*180 degreesSo that each interior angle is (n-2)*180/n degrees.Thus (n-2)*180/n = 108(n-2)*180 = 108*n180n - 360 = 108n72n = 360n = 5 sides.


What is the number of sides of a re gular polygon if one interior angle measures 108?

A polygon with interior angle measures of 108 would be a pentagon


How many sides does a polygon with an interior angle measure of 108 degrees have?

If its a regular pentagon then it will have 5 sides


What is the measure of the interior angles of a regular polygon if each exterior angle measures 72 degrees?

It is a 5 sided regular pentagon and each interior angle measures 108 degrees