8*12
3*12 + 6*186*12 + 4*18
9*12 + 2*18
12*12.
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
The sum of 36 and 144 is 180.
144
The sum is 144 if 60 is included, 84 if not.
8
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
There are 3 combinations - (1, 3), (2, 2), (3, 1) - that will result in a sum of four. Using fair d6 dice, there are 36 possible combinations - 6 on each die, 6 x 6 = 36. Thus there is a 3/36 = 1/12 = 0.0833.. = 8.3% probability.
The sum of 12 and 132 is 144
The sum of 72 and 144 is 216.
The sum of 36 and 144 is 180.
3.6.8 = 144
144
The sum is 154.
144/3 = 4848 + 3 = 51
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
no
Pi to 144 decimal places is written thus: 3.14159265358979323846264338327950288419716939937510 58209749445923078164062862089986280348253421170679 82148086513282306647093844609550582231725359 The sum of these first 144 decimal digits (after the decimal point) is 666.