Q: What prime number gives a remainder when divided by 12?

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237 is a COMPOSITE number. Since it is divided by 3 and gives a quotient of 79 (which is a prime factor of 237) and remainder as 0.

The answer is 51

Unless they are divided by themselves or one, they will always have a remainder.

A prime number is a number that can only be divided by 1 or itself. A composite number is a number which can be divided by a number other than itself or 1 and not leave a remainder. 178 divided by 2, for example, equals 89 (89 + 89 = 178). Since 2 is not dividing 178 by 1 or by itself and leaves no remainder, it is a composite number.

You know when you have a remainder once you have divided and all of the spots above the number being divided (the answer) have numbers. If you don't have zero by then, that last number is the remainder. If you want to figure it out without dividing, check a prime numbers chart.

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3 divided by 2 goes once, remainder one.

3 divided by 2 gives 1r1

If the number is divided by 119, it cannot be a prime!

237 is a COMPOSITE number. Since it is divided by 3 and gives a quotient of 79 (which is a prime factor of 237) and remainder as 0.

the number can be divided without a remainder

The answer is 51

127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.

prime factor = prime number which can be divided into the given number with no remainder ie 2

A prime number can be divided, without a remainder, only by itself and by 1 The question needs for information!

The answer is 1. The smallest prime is 2 and the greatest prime (of however many digits) must be odd. The remainder of ANY odd number when divided by 2 must be 1.

A prime number can be divided, without a remainder, only by itself and by 1. Zero and 1 are not prime numbers.

If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3