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The figure could be a rectangle with length 6.79 and width 2.21(2dp).

Area (A) of a rectangle = Length (L) x Width (W) = 15 : Then W = 15/L

Perimeter = 2(L + W) = 18 : substituting for W then :-

2(L + 15/L) = 18 : 2L + 30/L = 18 : 2L2 - 18L + 30 = 0

Solving for a quadratic equation gives L = (18 ± √84) ÷ 4 = 4.5 ± √5.25 = 4.5 ± 2.29(2dp)

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Q: What shape has fifteen square units as an area and eighteen units as a perimeter?
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