Q: What shape has more than 2 diagonals?

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Any quadrilateral (4-sided shape) has 2 diagonals.

There is none. A 5 sided shape is a pentagon but that has 10 diagonals, not 2.

All quadrilaterals (four sided shapes) have 2 diagonals.

A nanogon has no diagonals because there is no such shape. A nonagon, on the other hand, has 9*(9-3)/2 = 27 diagonals.

The formula for determining the number of diagonals in a shape is n(n-3)/2 where n=vertices, (corners or intersections of geometric shapes). For an eight sided shape we replace n with 8. 8(8-3)/2 8(5)/2 (8x5)/2 40/2=20 An octagon contains 20 diagonals. For a further example we can determine the diagonals in a shape with 5 sides: 5(5-3)/2 5(2)/2 (5x2)/2 10/2=5 A Pentagon contains 5 diagonals.

Related questions

Any quadrilateral (4-sided shape) has 2 diagonals.

There is none. A 5 sided shape is a pentagon but that has 10 diagonals, not 2.

All quadrilaterals (four sided shapes) have 2 diagonals.

There are 275 diagonals in a shape with 25 sides. The formula is n*(n-3)/2

1/2*(1002-300) = 4850 diagonals

There are 7*(7-3)/2 = 7*4/2 = 14 diagonals.

Number of diagonals = 18*(18-3)/2 = 135

A nanogon has no diagonals because there is no such shape. A nonagon, on the other hand, has 9*(9-3)/2 = 27 diagonals.

The formula for determining the number of diagonals in a shape is n(n-3)/2 where n=vertices, (corners or intersections of geometric shapes). For an eight sided shape we replace n with 8. 8(8-3)/2 8(5)/2 (8x5)/2 40/2=20 An octagon contains 20 diagonals. For a further example we can determine the diagonals in a shape with 5 sides: 5(5-3)/2 5(2)/2 (5x2)/2 10/2=5 A Pentagon contains 5 diagonals.

1/2*(602-180) = 1710 diagonals

5(5-3)/2. That it is the formula so that shape would have 5 diagonals. n(n-3)/2 where n is the number of sides

The answer depends on whether the shape is 2-dimensional or 3-d. For a 2-dimensional polygon with n sides, the minimum number is n-3 diagonals.