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It will have 3 equal sides and each of its 3 vertices will touch the circumference of the circle at 120 degree intervals.

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8y ago
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6mo ago

An equilateral triangle inscribed in a circle has three sides that are equal in length and three angles that are each 60 degrees. The center of the circle is also the intersection point of the triangle's perpendicular bisectors.

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Q: What shows an equilateral triangle inscribed in a circle?
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DFN: we call a triangle equilateral if all sides of the triangle are the same length DFN:we call two triangles similar if corresponding angles are equal, and corresponding sides are proportional. First show that all corresponding sides are proportional: Consider a equilateral triangle with side lengths 1, all other equal lateral triangles sides can be expressed as S*(1), where S is some scalar. Hence all equilateral triangles sides are proportional to each other. Next, show that all corresponding angles are equal: The angle between two sides of a triangle is related to the length of the sides. These relationships are called sin, cos, and tan. Knowing that the cos(x), where x is one of the angles in the triangle, is the adjacent divided by the hypotenuse we see that cos(x)=(1/2)c/a, since a = c (because its equal lateral) we are left with cos(x)=(1/2) which means x = 60 degrees. this can be applied to all three angles, which shows that all three angles are 60 degrees. / \ / | \ a / | \ b /__ |__\ c We have now shown that all equal lateral triangles are similar because they all have proportional sides, and they all have equal angles.