To calculate the wire size, a system voltage is needed.
To convert amps into watts a voltage is needed. Watts = Amps x Volts.
300kva equals zero amps. Voltage is needed to answer this question.
Watts = Volts x Amps for an incandescant bulb. So Amps = 600/120.
To answer this question the voltage of the generator is needed. I = W/E. I = 40000/Volts
The wire size used in a service entrance distribution panel is governed by the size of the services over current device. The larger the service, the larger the fault current could be, the larger the ground wire to carry the fault current to ground. If the largest service conductor carries 100 amps use a #8, 200 amps - #6, 400 amps - #3, 600 amps - #1, 800 amps - 1/0 and over 800 amps - 2/0 for the ground wire. <<>> Golden Valley Electric Assoc. in Alaska requires #4AWG copper wire for a ground from the breaker box to earth ground rod. The same goes from the service entrance panel on the pole.
#8 copper
64 AMPS
25 amps
To convert amps into watts a voltage is needed. Watts = Amps x Volts.
The Full Load Amps, FLA is a rating for each winding of the motor. In this case the motor actually needs 4 amps running through it. As current needs to go somewhere (perferably not to ground) the 4 amps will circulate on you 2 Hots, the neutral isn't needed. 4A in, 4A out.
2.5 sqmm cu cable current carrying capacity is 19 amps.
300kva equals zero amps. Voltage is needed to answer this question.
You cannot increase voltage by adding amps.
30 amps
Watts = Volts x Amps for an incandescant bulb. So Amps = 600/120.
1162.5 amps
To answer this question the voltage of the generator is needed. I = W/E. I = 40000/Volts