First 125 numbers sum to 125/2 x 126, so first 125 even numbers sum to double that ie 125 x 126 = 15750
The square root of 125 is 11.180
The numbers are 68.5 and 56.5
25 is a square number, and the sum of 9 and 16 is 25. 9 and 16 are also square numbers.
Not unless at least one of the numbers is zero.
The numbers are 125 and 126.
525 + 125 = 650
The answer will depend on which five square numbers!The answer will depend on which five square numbers!The answer will depend on which five square numbers!The answer will depend on which five square numbers!
The sum of all the odd numbers between 1 and 499 is 62500, because there are 125 pairs adding up to 500. 125 x 500 = 62500
They are simply: 100+25 = 125
You can. Just add the numbers together, and find their square root. One plus three is four; the square root of the sum is two.
The average is the sum of the numbers in the set divided by the number of numbers in the set. In this case it is (125+143+134)/3=134.
They are: 25+36+64 = 125
The sets of numbers that are the Square root of 5 are: 25 125
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
The answer is 385
121 123 125 127
to find the root-sum square of n numbers you square each number, add them, then take square root of sum For exanple root sum square of 2,3, and 4 is square root of (4+9+16) = sqrt(29) = 5.39
1. Design an algorithm to compute sum of the squares of n numbers?