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Number of sides minus two equals number of diagonals drawn from one vertex.

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Q: What statement can you make about the number of diagonals that can be drawn from one vertex in a polygon?
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Related questions

What can you say about the relationship of the number of diagonals that can be drawn from each vertex of a polygon?

The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon


How many diagonals can you drawn from one vertex in a 35 sided polygon?

A diagonal of a polygon is a segment drawn from one vertex to another non-adjacent vertex in a polygon. This leaves 32 diagonals that can be drawn from one vertex in a 35 sided polygon.


How many diagonal can be drawn from a regular hexagon from one vertex?

5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.


How many diagonals does a 8 sided polygon have?

An eight-sided polygon has 8 vertices. Consider1st vertex = 7 diagonals to other vertices2nd vertex = 6 diagonals to other vertices (since one has now been used)3rd vertex = 54th vertex = 45th vertex = 36th vertex = 27th vertex = 18th vertex = 0, so7+6+5+4+3+2+1 = 28Improved Answer:-Formula for finding diagonals of a polygon 0.5*(n2-3n) when n is the number of sides0.5*(82-24) = 20 diagonals


How many triangles can be formed by the diagonals of one vertex of a four-sided polygon?

Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.


What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?

You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.


How many diagonals can be drawn from one vertex of a polygon of 50 sides?

47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.


If in a 54 sided polygon all possible diagonals are drawn from one vertex they divide the interior of the polygon into how many regions?

In a 54-sided polygon, 53 possible diagonals can be drawn from one vertex to another. These diagonals will not intersect. Therefore, the interior will be divided into 54 regions by the 53 diagonals plus the two sides of the original polygon that adjoin the vertex from which the diagonals are drawn.


What polygon has 4 diagonals from one vertex?

Heptagon


What polygon has 3 diagonals from one vertex?

An hexagon


How many diagonals can be drawn from any vertex of a 20-sided polygon?

It is 18 diagonals


What is the connectionbetween the number of sides of the polygon and the number of triangles into which it may be divided by drawing diagonals from one vertex?

Number of sides minus 2 equals the number of triangles within the polygon.