0
It is: 0 because 205 = 0
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
What is X to the 0 power over x to the -5 power?
5
What is 6x squared plus 4x equals 0?
6x^2+4x=0 Divide everything by two 3x^2+2x=0 factor out an x x(3x+2)=0 Zero Product Property states that you can break apart the product when it is equal to zero because for this to occur either one or both of the factors must equal 0. x=0 or 3x+2=0 3x=-2 x=-2/3
What is 3 to the power of x minus 2 times 3 to the power of x minus 2?
x5
How do you solve x³-4x equals 0 algebraically?
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
Formula of quadratic equation if roots are given?
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
How do you solve x - x x?
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
If The product of x and negative 4 is 8 more than 2 added to negative 5 times that number what equation could be used to solve for x?
x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5
What is X to the 0 power over x to the -5 power?
5
What are the real roots of x5 - 2x4 - 24x3 equals 0?
x5 - 2x4 - 24x3 = 0 x3(x2 - 2x - 24) = 0 x3(x2 + 4x - 6x - 24) = 0 x3(x - 6)(x + 4) = 0 x = {-4, 0, 6}
What is the product of the roots of the equation 2xsquare-x-2 equals 0?
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
What is 6x squared plus 4x equals 0?
6x^2+4x=0 Divide everything by two 3x^2+2x=0 factor out an x x(3x+2)=0 Zero Product Property states that you can break apart the product when it is equal to zero because for this to occur either one or both of the factors must equal 0. x=0 or 3x+2=0 3x=-2 x=-2/3
Why are there two solutions to quadratic equations?
In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.
What is x cubed divided by square root of x?
x3/x1/2 = x5/2.
What is the product of 7 and 0?
Product = Multiply7 x 0 = 0
What is the product of the 2 solutions of the equation x'2 4'x-21 equals 0?
3 x - 7 = -21
What is 3 to the power of x minus 2 times 3 to the power of x minus 2?
x5
What number has prime factorization 2 x 2 x3 x5?
60
