It depends on whether or not the tetrahedron is regular. There is nothing in the question to indicate that it might be regular. In that case the easiest way to calculate the surface area is to sum the areas of each of its 4 faces.
The same volume of an object, The simplest regular tetrahedron polyhedron, calculate the surface area. The surface area is pentahedral small surface area than the regular tetrahedron Regular hexahedron surface area than the surface area is small pentahedral . . . . If it is known is N-face surface area of ​​the body, there are N +1 is smaller the surface area of ​​the surface When N tends to infinity for a long time, Serve the sphere surface. ------mecose
If each edge is 5 units long, then the total surface area is 5*sqrt(3) = 8.6603 square units, approx.
A tetrahedron is a solid figure with four triangular faces. As these may or may not be regular (all the same), the formula is to add the area of all four together. The formula for the area of a triangle is 1/2(base x height).
If its a triangular based pyramid (tetrahedron) then it will have 4 equilateral triangle faces and so find the area of one face and multiply it by 4 to give the total surface area.
The total surface area! The total surface area! The total surface area! The total surface area!
A regular octahedron has 8 faces. If the total surface area is 32 square inches then each face have a surface area equal to one eighth of this. 32/8 = 4 so the surface area of each face is 4 square inches
It is not possible to answer the question because the shape of the base is not known. As a result the surface area of the base, and hence the total surface area cannot be calculated.
It is called "the total surface area".
If it is a 4 faced tetrahedron pyramid then its complete surface area is 4*80 =320 square centimetres