1, 2 and 18 (when multiplied together)
1, 2 and 33 (when added together)
In each case, there are infinitely more alternatives.
2 x 3 x 6 = 36
9 and 36
Assuming you mean how to solve what three consecutive numbers sum to some value: Divide the sum by three to get the middle number. The other two numbers are one less than this and one more than it. example: Which three consecutive numbers sum to 108? 108 ÷ 3 = 36 → The other two numbers are 36 - 1 = 35 and 36 + 1 = 37 → The three numbers are 35, 36, 37. 35 + 36 + 37 = 108 as required.
12, 36 and 48
The numbers are 32, 34, 36, 38 and 40.
The three square numbers that makes up 36 are 1,2, and 18
2 x 3 x 6 = 36
11 + 12 + 13 =36
17+19 = 36
72 = 36 + 36
How about: 6+6+24 = 36 as an example
10, 12, 14 are the consecutive even #'s that equal 36
11, 12, and 13
25 and 11
9 and 36
31 and 5
29 and 7