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There are infinitely many answers.

Let A be any number greater than or equal to sqrt(10). There are infinitely many choices for A.

Then let B = 10/A.

A*B = A*(10/A) = 10. Every time.

This also applies to all values of A that are less than or equal to -sqrt(10). In this case both A and B will be negative.

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13y ago

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