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Isosceles Triangle, it has 2 sides the same and 1 side different.

Q: What triangle has 2 sides that r different?

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We know that R = a/2sinA area of triangle = 1/2 bc sinA sin A = 2(area of triangle)/bc R = (a/2)*2(area of triangle)/bc R = abc/4*(area of triangle)

I hope you want to know the Perimeter. Perimeter is the total length of the boundary of the region bounded by a shape. For a rectangle it is the sum of the 4 bounding sides, or 2*(L+B), where L is Length of the rectangle and B is Breadth of the rectangle. For a Triangle it is the sum of the 3 sides. If you consider an equilateral triangle. By property the 3 sides of an equilateral triangle are equal. Hence the Perimeter of an equilateral triangle is denoted as; 3*a, where a is the length of one of the sides of the triangle. It is possible that the perimeter of a rectangle is same as that of many different types of triangles. We can formulate a relationship for a special case where the perimeter of a rectangle is equal to the perimeter of an equilateral triangle; P(R) = P(ET), P(R) is perimeter of rectangle and P(EQ) is perimeter of Equilateral triangle. P(R)=2(L*B) = P(EQ) = 3*a; hence, a = (2/3)*(L*B) = P(R)/3. i.e., the sides of the Equilateral triangle are one thirds of the perimeter of the rectangle.

Triangle !

There is basically no difference. They are nothing more than 2 different visualizations of how we can graphically add two vectors.strictly if we say there is one and only difference is that---Triangle law of vector addition states that when 2 vectors r acting as the adjacent sides of a triangle taken in order. third side of the triangle will give the magnitude of th resultant 7 direction is in opposite order.Parallelogram law of vector addition states that if 2 vectors r acting as the adjacent sides of a parallelogram, then the diagonal of parallelogram from the point of intersection of two vectors represent their resultant magnitude & direction.

It can measure anything as long as the sides are all of different length and no angles are equal and the triangle has no lines of symmetry. If u r a member plz leave a note on my message board. Smiley bubble xxx

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We know that R = a/2sinA area of triangle = 1/2 bc sinA sin A = 2(area of triangle)/bc R = (a/2)*2(area of triangle)/bc R = abc/4*(area of triangle)

I hope you want to know the Perimeter. Perimeter is the total length of the boundary of the region bounded by a shape. For a rectangle it is the sum of the 4 bounding sides, or 2*(L+B), where L is Length of the rectangle and B is Breadth of the rectangle. For a Triangle it is the sum of the 3 sides. If you consider an equilateral triangle. By property the 3 sides of an equilateral triangle are equal. Hence the Perimeter of an equilateral triangle is denoted as; 3*a, where a is the length of one of the sides of the triangle. It is possible that the perimeter of a rectangle is same as that of many different types of triangles. We can formulate a relationship for a special case where the perimeter of a rectangle is equal to the perimeter of an equilateral triangle; P(R) = P(ET), P(R) is perimeter of rectangle and P(EQ) is perimeter of Equilateral triangle. P(R)=2(L*B) = P(EQ) = 3*a; hence, a = (2/3)*(L*B) = P(R)/3. i.e., the sides of the Equilateral triangle are one thirds of the perimeter of the rectangle.

A TRIANGLE!!! DUHH! SOME PEOPLE R DUMBOS A triangle, three sides, three angles.

Triangle !

all the sides r the same length

#include <stdio.h> main() { int r,b,h; printf("Enter the value of Base and Hight"); scanf("%d%d",&b,&h); r = ((b*h)/2); printf("Area of Triangle=%d",r); }

sin theta and csc theta are reciprocal functions because sin = y/r and csc = r/y you use the same 2 sides of a triangle, but you use the reciprocal.

There is basically no difference. They are nothing more than 2 different visualizations of how we can graphically add two vectors.strictly if we say there is one and only difference is that---Triangle law of vector addition states that when 2 vectors r acting as the adjacent sides of a triangle taken in order. third side of the triangle will give the magnitude of th resultant 7 direction is in opposite order.Parallelogram law of vector addition states that if 2 vectors r acting as the adjacent sides of a parallelogram, then the diagonal of parallelogram from the point of intersection of two vectors represent their resultant magnitude & direction.

It can measure anything as long as the sides are all of different length and no angles are equal and the triangle has no lines of symmetry. If u r a member plz leave a note on my message board. Smiley bubble xxx

The isosceles triangle of least area that can be circumscribed about a circle of radius r turns out to be not just isosceles, but also equilateral. Each side has length 2r x ( 3 )0.5 . The area is r2 x (27)0.5 . Thanks are due to litotes for pointing out that the original answer did not actually answer the question ! tpm Since the equilateral triangle is also an isosceles triangle, we can say that at least area that can be circumscribed to a circle is the area of an equilateral triangle.If we are talking only for isosceles triangle where base has different length than two congruent sides, we can say that at least area circumscribed to a circle with radius r, is the area of an isosceles triangle whose base angles are very close to 60 degrees. Solution: Let say that the isosceles triangle ABC is circumscribed to a circle with radius r, where BA = BC. We know that the center of the circle inscribed to a triangle is the point of the intersection of the three angle bisectors of the triangle. Let draw these angle bisectors, and denote with D the point where the bisector drawn from the vertex, B, of the triangle, intersects the base AC. Since the triangle is an isosceles triangle, then BD bisects the base and it is perpendicular to the base. So that AD = DC, OD = r, and the triangles ADB and AOD are right triangles (O is the center of the circle). In the triangle ADB, we have:tan A = BD/AD, so that AD = BD/tan A In the triangle AOD, we have:tan A/2 = OD/AD, so that AD = r/tan A/2, and AC = 2r/tan A/2 Therefore,BD/tan A = r/tan A/2, andBD = (r tan A)/tan A/2 Area of triangle ABC = (1/2)(AC)(BD) = (1/2)(2r/ tan A/2)[(r tan A)/tan A/2] = (r2 tan A)/tan2 A/2 After we try different acute angles measure, we see that the smallest area would be: If the angle A= 60⁰,then the Area of the triangle ABC = r2 tan 60⁰/tan2 30⁰ ≈ 5.1961r2 If the angle A= 59.8⁰,then the Area of the triangle ABC = (r2 tan 59.8⁰)/tan2 29.9⁰ ≈ 5.1962r2

If you mean vertices of (-2, 9) (7, -3) and (-2, -3) then it is a right angle triangle with an hypotenuse of 15 and sides of 9 and 12 that all add up to 36 which is the perimeter of the triangle.

Four sides of a pyramid are triangular-shaped, meaning they have three sides. The fifth side is square-shaped, meaning it's four-sided.