This is easily figured using a system of equations:
x + y = 3
xy = 12
Then y = 3 - x
x(3 - x) = 12
3x - x^2 = 12
-x^2 + 3x - 12 = 0
x^2 - 3x + 12 = 0
Using the quadratic formula gives us the two solutions 1/2 (3 + i √39) and 1/2 (3 - i √39). Note that the solutions are complex numbers.
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
-9
7 and 12
-4 and -3
-11 and -1
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
No integers work
-9
7 and 12
-4 and -3
5 and 7
-11 and -1
The integers 2 and 10 have a product of 20 and a sum of 12.
-3 and -4
8+4=12
-9
3 and 4. 3+4=7 3x4=12