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This is easily figured using a system of equations:

x + y = 3

xy = 12

Then y = 3 - x

x(3 - x) = 12

3x - x^2 = 12

-x^2 + 3x - 12 = 0

x^2 - 3x + 12 = 0

Using the quadratic formula gives us the two solutions 1/2 (3 + i √39) and 1/2 (3 - i √39). Note that the solutions are complex numbers.

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11y ago
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Q: What two integers have a sum of 3 and a product of 12?
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