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Let your numbers be x and y So you can write the equations... x+y=13 and xy=36 Solving the first equation you get y=13-x Using substitution (plugging the equation above into the second equation) x(13-x)=36 13x - x^2 = 36 Set your equation equal to zero... x^2 - 13x + 36 = 0 Factoring... (x-9)(x-4)... so, x=9 and x=4 Plugging these values back into your original equations gives you that one of your answers is 9 and the other is 4.

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Q: What two numbers have a sum of 13 and a product of 36?
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