They are: 78 and 63
The numbers are 45, 47, and 49.
141
The LCM of 3 and 47 is 141.
141
sum means numbers which add up to 141 41 is an obvious one which leaves you with 100 simplest thing would to be divide 100 by 2 but that gives 50 which is an even number so use 49 and 51. 41 + 49 + 51 = 141 Note, these aren't the only 3 odd numbers which sum to 141, that just seemed the easiest way to work it out to me.
two prime numbers whose product is 141 = 3 & 47
The product of 141 multiplied by 47 is 6627
The numbers are 45, 47, and 49.
I don't think there's a solution to this problem. Let's work it through.Two consecutive integers: x & y. So y = x + 1.Product is 34 more than sum. Product (x*y) = sum(x+y) +34Substitute [y=x+1] into second equation: x*(x+1) = x + (x+1) + 34x2 + x = x + x + 1 + 34 --> x2 + x - 2*x - 35 = 0 --> x2 - x - 35 = 0 (quadratic)In the quadratic formula: a = 1, b = -1, c = -35, so we have (1 ± sqrt[1 - 4*(-35)])/(2*1) = (1 ± sqrt(141))/2; sqrt(141) is irrational, so the solution is not integers. Someone else can maybe check my work.
The greatest common multiple of any set of integers is infinite.
Possible the simplest math question ever. -420 / 3 = -140. So the numbers you need are -139 , -140 , -141.
This would be impossible. The closest result you can get is 45 + 47 + 49 = 141
All integers greater than 1 are one or the other.
141
The LCM of 3 and 47 is 141.
141
1, 3, 5, 15, 47, 141, 235, 705.