For any integer value of x â‰¥ 0, there are two values, Â±y, such that x! = y2. For example, if x = 3 then x! = 6 and so y = Â±âˆš6
Speed equals distance divided by time. By rearranging that formula, we get time equals distance divided by speed.
Any two values which total 25
j=-3 and k=2
Wonderful. Thanks for sharing. If we had another equation in addition to that one, then we could find unique values for 'x' and 'y' that satisfy both. With only this equation, there are an infinite number of pairs of values that satisfy it, just as long as y = 0.75x + 2.75 .
Factorial (n) = n * Factorial (n-1) for all positive values n given Factorial (1) = Factorial (0) = 1. Pseudo-code: Function: factorial, f Argument: positive number, n IF n<=1 THEN RETURN 1 ELSE RETURN n * f(n-1) END IF
It's a single linear equation in two variables. The graph of the equation is a straight line; every point on the line is a set of values that satisfy the equation. In other words, there are an infinite number of pairs of (x,y) values that satisfy it. In order to figure out numerical values for 'x' and 'y', you would need another equation.
The factorial function is the product of a single scalar value and all of its smaller values down to one. As such, it does not make sense to ask how to find the factorial of an array. Certainly, one could determine the factorial of each element of the array; simply setup a loop that iterates through the array and then performs the factorial function.
Solutions of an equation are the set of values which satisfy it.