x = 90
y = 89
For any integer value of x ≥ 0, there are two values, ±y, such that x! = y2. For example, if x = 3 then x! = 6 and so y = ±√6
-4
j=-3 and k=2
Any two values which total 25
Wonderful. Thanks for sharing. If we had another equation in addition to that one, then we could find unique values for 'x' and 'y' that satisfy both. With only this equation, there are an infinite number of pairs of values that satisfy it, just as long as y = 0.75x + 2.75 .
For any integer value of x ≥ 0, there are two values, ±y, such that x! = y2. For example, if x = 3 then x! = 6 and so y = ±√6
-4
10.
mean
Speed equals distance divided by time. By rearranging that formula, we get time equals distance divided by speed.
j=-3 and k=2
Any two values which total 25
Wonderful. Thanks for sharing. If we had another equation in addition to that one, then we could find unique values for 'x' and 'y' that satisfy both. With only this equation, there are an infinite number of pairs of values that satisfy it, just as long as y = 0.75x + 2.75 .
It's a single linear equation in two variables. The graph of the equation is a straight line; every point on the line is a set of values that satisfy the equation. In other words, there are an infinite number of pairs of (x,y) values that satisfy it. In order to figure out numerical values for 'x' and 'y', you would need another equation.
Both 143 and 33 can be divided by 11. The number 11 is a common divisor of these two values, as 143 divided by 11 equals 13, and 33 divided by 11 equals 3. Additionally, the greatest common divisor (GCD) of 143 and 33 is 11.
The exclamation point is the symbol for the factorial function. For integer values of n, n! = 1*2*3*...*n The factorial is critical for calculating numbers of permutations and combinations.
No, there is no single number that equals both 21 and 34, as they are distinct values. A number can only be equal to one specific value at a time. Therefore, no number can satisfy the condition of being equal to both 21 and 34 simultaneously.