Q: What whole number between 2 and 40 can be divided by 4 with a remainder of 2 and can be divided by 5 with a remainder of 1?

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2346.6667

0.6667

12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.

divisible

No, if you have a remainder larger than your whole number, you must have divided incorrectly. very good

266 / 2 = 133 remainder 0

1098765433 will have a remainder of 1.

8

Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7

11.1324

Any whole number can be divided by 1 without leaving a remainder.

A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.

Any whole number that can be divided into another whole number with out any remainder is a factor of that number.

Yes, it can happen. Wonders will never cease!

0.4444

0.625

It is: 105

Because every number can be divided by one with no remainder.

Divide each of these numbers by 11, and the remainder is 5.

It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.

The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.

90 divided by 25 is 3 with remainder 15

Because every [whole] number can be divided by '1' without a remainder. ' 1 ' fits into every [whole] number a whole number of times.

Any whole number that ends with a '9'.(Even '9' itself is one of them. When 9 is divided by 10, the answer is zero with remainder 9.)

12.0123