2R or two times the radius.
Yes. D = 2R
Diameter equal 2r (d=2r) So if your Diameter is 28 then: 28=2r (divide 2 on both sides) 14=r therefor the radius is 14
Suppose the radius is R cm. Then the perimeter of the rectangle is 2*(3+R) = 6 + 2R cm. The length of the arc of the semicircle is pi*R and the length of the diameter is 2*R so the perimeter of the semicircle is pi*R + 2R The two perimeters are equal so 6 + 2r = pi*R + 2R That is, 6 = pi*R and so R = 6/pi
|2r + 9| = 5 So 2r + 9 = 5 or 2r + 9 = -5 so that 2r = -4 or 2r = -14 r = -2 or r = -7
If: -7 = 7-2r Then: r = 7
2r + 5 - - 1 When simplified: 2r + 6
4r2-25 = (2r)2-52 = (2r-5)(2r+5)
2r-1=9 2r =10 r =5
4r - 25 does not factor. If that were 4r2 - 25, it would be the difference of two squares, which factors to (2r - 5)(2r + 5)
If: 3r-8 = 2-2r Then: 5r = 10 And: r = 2
The radius is directly related to the circumference of a circle by C=π 2R so it would get proportionately larger as the circumference grows. If you start with C=π 2R where 2R=C/π then change C to C2=3C then 2R2 becomes C2/π or 3(2R)/π
No, no it can't. Circumference = 2r*pi Area = pi*r2 For the area to equal the circumference pi*r2 = pi*2r so divide both sides by pi r2 = 2r so divide both sides by r r = 2 Note that circumference is in units and area is in units squared i.e. radius = 2m, area = 12.56637m2 Ciercumference = 12.56637 m
2R = 2.5 inch x 3.5 inch
If: C = 2r Then: r = C/2
A math problem
It depends on what operations you are allowed to use, but if repeating decimals are allowed it is easy. I can't type a dot or bar over a digit to indicate a repeating decimal here, so I'll type .2r for .222222..., which is equal to 2/9. Thus 2/.2r is 9, so 2/.2r - 2 is 7, as required.
1d i posted a video on how to do this on youtube...go to www.youtube. com and search for soukoban 2l 3d 2r 2u 2d 2l 2u 2l 1u 2r 1u 2r 2d 2l 2d 2r 1u 1d 2l 3u 2l 1d 1r 1d 2l 3d 2r 2u 2d 2l 2u 2l 1u 2r 1u 2r 2d 2l 2d 2r 1u 1d 2l 3u 2l 1d
2r + 4 or 2*(r+2)
If: 7 -2r = 13 Then: r = -3
2r - 7 = 9 (+7) (+7) >> add 7 to both sides so that only 2r is on that side 2r = 16 2r/2 = 16/2 >> divide both sides by 2 to isolate the variable r=8 >>16 divided by 2 is 8 which is your answer
The volume of a cube is L3. The volume of a sphere is 4/3 Ï€ r3 . If L=2r, Vcube=8r3. Comparing the volume of the cube with a side 2r and a sphere with a diameter of 2r where the r's are equal gives us: Vcube/Vsphere= (8r3)/(4/3 Ï€ r3 ) or (8x3)/(Ï€x4) As Ï€ roughly equals 3 the equation simplifies to: Vcube/Vsphere=2 or a cube with its side equal to the diameter of a sphere has a volume approximately twice that of the sphere.