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What would be the dimensions of the rectangle if the length is yd more than twice the width the area is 452?
Wiki User
∙ 6y ago
Let the length be 2x+1 and the width be x:-
And so: (2x+1) times x = 452 or 2x^2 +x -452 = 0
Using the quadratic equation formula x has a positive value of: 14.78537495
Width = 14.78537495 yds and length is 2*(14.78537495)+1 = 30.5707499 yds
Check: width times length = 451.9999998 which rounds to 452 square yards
Wiki User
∙ 6y ago
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