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I would subtract [ 2x (4x + 9) ] .
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If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11
How do you factor 8x squared plus 18x-18?
2(4x - 3)(x + 3)
How do you divide the following expression. Assume that the denominator is nonzero. 18x9 -12x7 -8x6 -2x3 all divided by -2x2?
In dividing (18x⁹ -12x⁷ -8x⁶ -2x³) ÷ -2x² you could do long division, but as the divisor contains a single term like a normal fraction each term of the dividend can be divided by the divisor and summed together: (18x⁹ -12x⁷ -8x⁶ -2x³) ÷ -2x² = (18x⁹ -12x⁷ -8x⁶ -2x³)/(-2x²) = 18x⁹/(-2x²) + -12x⁷/(-2x²) + -8x⁶/(-2x²) + -2x³/(-2x²) = (18 ÷ -2)(x⁹ ÷ x²) + (-12 ÷ -2)(x⁷ ÷ x²) + (-8 ÷ -2)(x⁶ ÷ x²) + (-2 ÷ -2)(x³ ÷ x²) = -9x⁹⁻² + 6x⁷⁻² + 4x⁶⁻² + 1x³⁻² = -9x⁷ + 6x⁵ + 4x⁴ + x
What is 8x subtract 3 equals 6?
8x-3=6 8x=9 x=9/8=1 1/8=1.125
The sum of two numbers is 18 and a half The first number is 4times the second What are the two numbers?
If you say the second number is x, then the first number would be 8x.Therefore x+8x=189x=18x=2(second number)8x=16( first number)
What is -8x subtract -2x?
-6
If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11
How do you factor 8x squared plus 18x-18?
2(4x - 3)(x + 3)
Subtract 8x plus 6 - x plus 4?
Subtract it from WHAT!
7 plus 8x-5 equals 8x plus 7-5x?
7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1
How do you divide the following expression. Assume that the denominator is nonzero. 18x9 -12x7 -8x6 -2x3 all divided by -2x2?
In dividing (18x⁹ -12x⁷ -8x⁶ -2x³) ÷ -2x² you could do long division, but as the divisor contains a single term like a normal fraction each term of the dividend can be divided by the divisor and summed together: (18x⁹ -12x⁷ -8x⁶ -2x³) ÷ -2x² = (18x⁹ -12x⁷ -8x⁶ -2x³)/(-2x²) = 18x⁹/(-2x²) + -12x⁷/(-2x²) + -8x⁶/(-2x²) + -2x³/(-2x²) = (18 ÷ -2)(x⁹ ÷ x²) + (-12 ÷ -2)(x⁷ ÷ x²) + (-8 ÷ -2)(x⁶ ÷ x²) + (-2 ÷ -2)(x³ ÷ x²) = -9x⁹⁻² + 6x⁷⁻² + 4x⁶⁻² + 1x³⁻² = -9x⁷ + 6x⁵ + 4x⁴ + x
Subtract 6x-10 from 8x-8?
(8x - 8) - (6x - 10) = ?8x - 8 - 6x + 10 = ?8x - 6x + 10 - 8 = ?2x + 2 = ?The answer is (2x + 2)
What is 8x subtract 3 equals 6?
8x-3=6 8x=9 x=9/8=1 1/8=1.125
The sum of two numbers is 18 and a half The first number is 4times the second What are the two numbers?
If you say the second number is x, then the first number would be 8x.Therefore x+8x=189x=18x=2(second number)8x=16( first number)
What is 8x to the second power?
8x to the second power is 64x2
What is a algebra puzzle?
An equation to figure out what the answer of "x" is. eg, Removing the brackets - 6(3x-2) = 2(8x+4) 18x-12 = 16x + 8 18x-16x = 8+12 2x = 20 x = 10
What is the answer to 8x plus 33 equals 7x plus 27?
8x + 33 = 7x + 27 Subtract 7x from both sides: x + 33 = 27 Subtract 33 from both sides: x = -6
