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Let the smallest integer be x. Since the consecutive even integers differ by 2, we have

x + 2(x + 2) = (x + 4) + 20
3x + 4 = x + 24 (subtract x and 4 from both sides)
3x - x - 4 + 4 = x - x - 4 + 24
2x = 20 (divide by 2 to both sides)
x = 10

Thus, the three consecutive even integers are 10, 12, and 14.

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Q: Whats the answer to Find three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third?
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